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Voltage Drop Calculator

Find the voltage drop in volts and percent for a copper or aluminum wire run, check it against the NEC 3 and 5 percent guidelines, and see the smallest wire size that fits.

Parallel sets, stranding and temperature
Quick examples
Voltage drop
7.92volts6.60% of 120 VOver 5% guideline

Above both the 3 percent branch and 5 percent total guidelines in the NEC informational notes.

The bar runs from 0 to 10 percent, with marks at the 3 and 5 percent guidelines.

Smallest wire for this run

3% branch guideline8 AWG
5% total guideline10 AWG

Checked with copper, stranded, 1 set at 75 °C, 20 A over 100 ft one way. Your 12 AWG is too small for both guidelines.

Voltage drop is one test. The wire must also have enough ampacity under NEC Table 310.16 for the load and breaker, which this calculator does not check.

Voltage at load112.08 Vwhat the load receives at 20 A
Power lost158.4 WI² × R heat in the conductors
Wire resistance0.396 Ωout and back, 200 ft of wire
Conductor area6,530 cmil3.31 mm² per NEC Table 8
Max run at 3%45.5 ftone way, same wire and load
Max load at 3%9.09 Aon this wire and length

Your calculation

The same steps the calculator runs, with your numbers.

  1. NEC Table 8, 12 AWG stranded uncoated copper: 1.98 Ω per 1,000 ft at 75 °C.
  2. One conductor: 1.98 × 100 ÷ 1,000 = 0.198 Ω.
  3. Voltage drop: 2 × 20 A × 0.198 Ω = 7.92 V.
  4. Percent: 7.92 ÷ 120 × 100 = 6.60%.
  5. Voltage at load: 120 − 7.92 = 112.08 V.
  6. Power lost: 2 × 20² × 0.198 = 158.4 W.
  7. Longest run at 3%: 0.03 × 120 ÷ (2 × 20 × 0.00198 Ω/ft) = 45.45 ft.
  8. K factor check: 2 × 12.9 × 20 × 100 ÷ 6,530 = 7.90 V (approximate).

Nearby wire sizes

The closest sizes above and below your wire, with the same load and run.

SizeDropPercentGuideline
18 AWG31.80 V26.50%Over 5%
16 AWG19.96 V16.63%Over 5%
14 AWG12.56 V10.47%Over 5%
10 AWG4.96 V4.13%3% to 5%
8 AWG3.11 V2.59%Within 3%
6 AWG1.96 V1.64%Within 3%
Your 12 AWG is left out because its drop is shown above. Same material, current, length, sets and temperature.

An estimate from conductor DC resistance. Electrical work must follow your local code and be done or inspected by a licensed electrician.

How the Voltage Drop Calculator Works

This voltage drop calculator estimates how many volts a wire run loses between the panel and the load, and what share of the system voltage that loss represents. It multiplies the load current by the resistance of the conductors, using the direct current resistance values in NEC Chapter 9, Table 8 for AWG and kcmil sizes, or the standard resistivity of copper and aluminum for metric mm² sizes. The result is compared with the 3 percent and 5 percent guidelines in the National Electrical Code informational notes.

Use it when planning a long branch circuit, a feeder to a garage or subpanel, an EV charger, a well pump, or a 12 V DC run in an RV or solar system. It also reports the voltage at the load, the power lost as heat, the longest run and largest load under 3 percent, and the smallest wire for each guideline.

Voltage drop (single phase or DC) = 2 × L × R × I ÷ 1,000 Voltage drop (three phase) = 1.732 × L × R × I ÷ 1,000 L = one way length in feet; R = ohms per 1,000 ft at 75 °C; I = load current in amps Percent drop = voltage drop ÷ system voltage × 100 Example: 20 A on 100 ft of 12 AWG stranded copper (1.98 Ω per 1,000 ft) at 120 V 2 × 100 × 1.98 × 20 ÷ 1,000 = 7.92 V 7.92 ÷ 120 × 100 = 6.6% drop; 120 − 7.92 = 112.08 V at the load

The factor of 2 covers current flowing out on one conductor and back on the other, so you always enter the one way distance. A balanced three phase circuit uses the square root of 3, about 1.732, because the phase currents return through the other phase conductors. A DC circuit is calculated exactly like a single phase circuit.

Voltage Drop Formula With Circular Mils (K Factor Method)

The K factor form replaces the table resistance with a constant divided by the conductor area in circular mils. A circular mil is the area of a circle 0.001 inch across (1 mm² is about 1,973.5 cmil). Multiplying a Table 8 resistance per foot by its area gives about 12.9 for uncoated copper and 21.2 for aluminum at 75 °C, the K values IAEI gives for voltage drop work.

VD = 2 × K × I × L ÷ CM (single phase or DC) VD = 1.732 × K × I × L ÷ CM (three phase) K = 12.9 for copper, 21.2 for aluminum; CM = area in circular mils Example: 2 × 12.9 × 20 × 100 ÷ 6,530 = 7.90 V (Table 8 method: 7.92 V) Wire size for a target: CM = 2 × K × I × L ÷ allowed VD 3% of 120 V = 3.6 V: 2 × 12.9 × 20 × 100 ÷ 3.6 = 14,333 cmil, so 8 AWG (16,510 cmil) Maximum length = CM × allowed VD ÷ (2 × K × I)

The K method is approximate because the product of resistance and area changes slightly from size to size. Across the sizes in this calculator it runs from 12.84 to 12.93 for stranded copper and from 21.13 to 21.25 for aluminum. The calculator uses the exact Table 8 resistance for the size you pick and shows the K factor result in the steps as a cross check.

AWG Wire Resistance Chart (Ohms per 1,000 Feet)

These direct current resistance values come from NEC Chapter 9, Table 8, at a conductor temperature of 75 °C, for Class B stranded uncoated copper and aluminum. They are the values the calculator uses for AWG and kcmil sizes.

SizeArea (cmil)Area (mm²)Copper Ω/1,000 ftAluminum Ω/1,000 ft
18 AWG1,6200.8237.9513.1
16 AWG2,5801.314.998.21
14 AWG4,1102.083.145.17
12 AWG6,5303.311.983.25
10 AWG10,3805.2611.242.04
8 AWG16,5108.3670.7781.28
6 AWG26,24013.300.4910.808
4 AWG41,74021.150.3080.508
3 AWG52,62026.670.2450.403
2 AWG66,36033.620.1940.319
1 AWG83,69042.410.1540.253
1/0 AWG105,60053.490.1220.201
2/0 AWG133,10067.430.09670.159
3/0 AWG167,80085.010.07660.126
4/0 AWG211,600107.20.06080.100
250 kcmil250,0001270.05150.0847
300 kcmil300,0001520.04290.0707
350 kcmil350,0001770.03670.0605
400 kcmil400,0002030.03210.0529
500 kcmil500,0002530.02580.0424

Solid wire, often used for 14 to 10 AWG in nonmetallic sheathed cable, has slightly lower resistance: Table 8 lists solid copper at 3.07 Ω for 14 AWG, 1.93 Ω for 12 AWG and 1.21 Ω for 10 AWG per 1,000 ft. Choose Solid under Stranding to use those values. Tinned or coated copper has higher resistance and is not covered here.

Metric cable sizes

For mm² sizes the calculator uses resistivity: 0.017241 Ω·mm²/m for annealed copper (100 percent IACS) and 0.028264 Ω·mm²/m for 61 percent IACS aluminum, both at 20 °C, corrected to the conductor temperature. At 75 °C copper becomes 0.017241 × [1 + 0.00393 × 55] = 0.020968 Ω·mm²/m and aluminum 0.034529 Ω·mm²/m. Dividing by the area gives 8.387 Ω per km for 2.5 mm² copper, 5.242 Ω for 4 mm² and 3.495 Ω for 6 mm².

Acceptable Voltage Drop: The NEC 3 Percent and 5 Percent Guidelines

The National Electrical Code (NFPA 70) does not set a general voltage drop limit. Informational Note No. 4 under Section 210.19(A) says branch circuit conductors sized to prevent a drop over 3 percent at the farthest outlet, with no more than 5 percent total on the feeder and branch circuit together, provide reasonable efficiency of operation. Informational Note No. 2 under Section 215.2(A) repeats the same guidance for feeders.

Section 90.5(C) states that informational notes are explanatory material, not enforceable requirements. Voltage drop is mandatory in a few places, such as Section 647.4(D) for sensitive electronic equipment, and it can become mandatory through local amendments, project specifications, or equipment instructions that Section 110.3(B) requires installers to follow. Subsection numbering shifts slightly between NEC editions, so check the edition your area enforces.

System voltage3 percent5 percent
12 V DC0.36 V0.6 V
24 V DC0.72 V1.2 V
120 V3.6 V6 V
208 V6.24 V10.4 V
230 V6.9 V11.5 V
240 V7.2 V12 V
277 V8.31 V13.85 V
480 V14.4 V24 V

Because the 5 percent figure covers the whole path from the service to the farthest outlet, a feeder that drops 2 percent leaves 3 percent for the branch circuit, while a short feeder at 1 percent leaves 4 percent.

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Meeting 3 percent does not mean the wire is large enough. Ampacity, overcurrent protection and terminal temperature ratings are separate NEC requirements that this calculator does not check.

Wire Size for Voltage Drop Over 100, 150 and 200 Feet

Voltage drop grows in direct proportion to length and current, so doubling the run doubles the drop. The table shows a 20 A load at 120 V on stranded copper, single phase, at several one way lengths.

Wire50 ft100 ft150 ft200 ft
12 AWG3.96 V (3.30%)7.92 V (6.60%)11.88 V (9.90%)15.84 V (13.20%)
10 AWG2.48 V (2.07%)4.96 V (4.13%)7.44 V (6.20%)9.92 V (8.27%)
8 AWG1.56 V (1.30%)3.11 V (2.59%)4.67 V (3.89%)6.22 V (5.19%)
6 AWG0.98 V (0.82%)1.96 V (1.64%)2.95 V (2.46%)3.93 V (3.27%)
4 AWG0.62 V (0.51%)1.23 V (1.03%)1.85 V (1.54%)2.46 V (2.05%)

At 100 feet, 8 AWG is the smallest copper size under 3 percent for this load, and at 200 feet it takes 4 AWG. The same 20 A at 240 V drops the same number of volts, but each volt is half the percentage, so 10 AWG at 100 feet comes in at 2.07 percent.

Maximum length for a 3 percent drop

Load and copper wire120 V240 V
15 A on 14 AWG38.2 ft76.4 ft
20 A on 12 AWG45.5 ft90.9 ft
30 A on 10 AWG48.4 ft96.8 ft
40 A on 8 AWG57.8 ft115.7 ft
50 A on 6 AWG73.3 ft146.6 ft
60 A on 4 AWG97.4 ft194.8 ft

These lengths assume the full current flows continuously, which gives a worst case. A circuit that rarely runs at full load drops less in practice. The pairs are examples, not ampacity ratings.

Voltage Drop for EV Chargers, Subpanels, Well Pumps and DC Systems

EV charger: 50 A at 240 V, 80 ft

6 AWG copper: 2 × 80 × 0.491 × 50 ÷ 1,000 = 3.93 V (1.64%) Longest run at 3% on 6 AWG with this load: 146.6 ft

An EV charger can draw full current for hours, so the circuit must also meet the charger instructions and the NEC sizing rules for the charging circuit.

Subpanel feeder: 100 A at 240 V, 150 ft

3 AWG copper: 7.35 V (3.06%); 2 AWG copper: 5.82 V (2.43%) 1/0 AWG aluminum: 6.03 V (2.51%); 2/0 AWG aluminum: 4.77 V (1.99%)

Feeder drop adds to every branch circuit fed from the subpanel. With 2 AWG copper at 2.43 percent, branch circuits have about 2.6 percent left under the 5 percent total. The full 100 A is a worst case; actual demand is usually lower.

Well pump: 10 A at 240 V, 250 ft

12 AWG: 9.9 V (4.13%); 10 AWG: 6.2 V (2.58%); 8 AWG: 3.89 V (1.62%)

Measure the full cable length from the panel or pump control box to the motor, including the depth down the well. Submersible pump installation manuals list maximum cable lengths for each motor, so follow them where they are stricter.

12 V and 24 V DC: solar, RV and low voltage lighting

12 V, 10 A, 20 ft, 10 AWG: 2 × 20 × 1.24 × 10 ÷ 1,000 = 0.496 V (4.13%) 12 V lighting, 8 A, 50 ft: 10 AWG 0.99 V (8.27%); 8 AWG 0.62 V (5.19%) Same lights at 24 V draw 4 A: 10 AWG 0.50 V (2.07%)

A low voltage run loses the same volts as a 120 V circuit carrying the same current, but each volt is a far larger share of the supply. Raising the system voltage lowers the current for the same power, which is why 24 V and 48 V battery systems allow longer runs on the same wire.

Copper vs Aluminum Wire and the Effect of Temperature

Table 8 is based on aluminum with 61 percent of the conductivity of annealed copper, so aluminum wire has about 1.64 times the resistance of copper of the same size (3.25 against 1.98 Ω per 1,000 ft for 12 AWG). Installers make up for it with a larger size. On a 50 A, 240 V circuit with a 100 ft run, 4 AWG aluminum drops 5.08 V (2.12 percent), close to the 4.91 V (2.05 percent) of 6 AWG copper, while 6 AWG aluminum drops 8.08 V (3.37 percent).

Resistance rises with temperature. NIST Handbook 100 gives the coefficient of standard annealed copper as 0.00393 per °C at 20 °C, and NIST Handbook 109 gives 0.00403 per °C for 61 percent conductivity aluminum. Referred to 75 °C those become 0.00323 and 0.00330, the values in note 2 of Table 8.

R at T = R at 75 °C × [1 + α × (T − 75)] 12 AWG copper at 60 °C: 1.98 × [1 + 0.00323 × (60 − 75)] = 1.884 Ω per 1,000 ft 12 AWG copper at 90 °C: 1.98 × [1 + 0.00323 × (90 − 75)] = 2.076 Ω per 1,000 ft Default circuit at 60 °C: 2 × 100 × 1.884 × 20 ÷ 1,000 = 7.54 V instead of 7.92 V From IACS: 10.371 Ω·cmil/ft × [1 + 0.00393 × 55] ÷ 6,530 × 1,000 = 1.93 Ω (solid 12 AWG)

IAEI notes that most terminals in new equipment are rated 75 °C, which is why Table 8 uses that temperature. A wire carrying much less than its rated current runs cooler, so the 75 °C result is slightly conservative for lightly loaded circuits.

Why Voltage Drop Matters

  • Heaters and lights. A resistive heater's output follows the square of the voltage, so a 6.6 percent drop cuts its output by about 12.8 percent. Incandescent and some LED lamps dim at the end of a long run.
  • Motors. A motor running below its rated voltage needs more current to carry the same load, which raises winding temperature. Starting current is several times running current, so a long run also causes deeper dips at startup.
  • Electronics and chargers. Many devices list a minimum input voltage in their instructions, and IAEI points out that listed equipment is meant to run within that range.
  • Wasted energy. The default circuit turns 158.4 W into heat in the wire at full load, about 1.27 kWh over 8 hours, energy you pay for without using.

How to Use the Calculator

  • Material and circuit. Copper or aluminum; Single phase / DC or Three phase.
  • Wire size. 18 AWG to 500 kcmil, or 1.5 to 240 mm².
  • Voltage. A preset or custom value; line to line for three phase.
  • Current and length. Load amps and one way distance in feet or meters.
  • Options. Parallel sets, solid wire and conductor temperature.

Common Mistakes

  • Entering the round trip length. The formula already doubles it, so the drop comes out twice as large.
  • Using the wrong voltage. A 120 V load on a 120/240 V panel is a 120 V circuit.
  • Forgetting the feeder. Branch drop adds to feeder drop.
  • Mixing metals. Aluminum needs its own resistance values.
  • Uneven parallel sets. Paralleled conductors must match in size and length.

Limitations of This Estimate

The calculator uses direct current resistance. In AC circuits, large conductors also have skin effect and inductive reactance, covered by NEC Chapter 9, Table 9. IAEI notes that Table 8 values are close to the Table 9 resistance values, but long feeders with large conductors and a low power factor may be designed with the Table 9 impedance method instead.

Metric results use nominal cable area; a data sheet gives the measured resistance of a specific cable. Motor starting current, harmonics and unbalanced loads are not modeled. Electrical work must follow your local code and be done or inspected by a licensed electrician.

Frequently Asked Questions

What is the acceptable voltage drop percentage?

The National Electrical Code suggests sizing branch circuit conductors so the voltage drop at the farthest outlet stays at or below 3 percent, with no more than 5 percent total for the feeder and branch circuit together. That guidance is in Informational Note No. 4 under Section 210.19(A) and Informational Note No. 2 under Section 215.2(A). Informational notes are explanatory and not enforceable on their own, but local amendments, project specifications and equipment instructions can make a limit mandatory. On a 120 V circuit, 3 percent is 3.6 V and 5 percent is 6 V.

How do you calculate voltage drop?

Multiply the load current by the resistance of the wire the current travels through. For a single phase or DC circuit, VD = 2 × L × R × I ÷ 1,000, where L is the one way length in feet and R is the conductor resistance in ohms per 1,000 feet from NEC Chapter 9, Table 8. For three phase, replace 2 with 1.732. Example: 20 A on 100 feet of 12 AWG stranded copper at 1.98 ohms per 1,000 feet gives 2 × 100 × 1.98 × 20 ÷ 1,000 = 7.92 V, which is 6.6 percent of 120 V.

What size wire do I need for 100 feet?

It depends on the current and voltage. For a 20 A load at 120 V over a 100 foot one way run, 12 AWG copper drops 7.92 V (6.6 percent), 10 AWG drops 4.96 V (4.13 percent) and 8 AWG drops 3.11 V (2.59 percent), so 8 AWG is the smallest copper size under 3 percent. The same 20 A load at 240 V drops half the percentage, so 10 AWG copper comes in at 2.07 percent. Always confirm the wire also has enough ampacity under NEC Table 310.16 for the load and breaker.

Is copper or aluminum wire better for voltage drop?

Copper has lower resistance, so it drops less voltage at the same size. In NEC Table 8, stranded 12 AWG aluminum measures 3.25 ohms per 1,000 feet against 1.98 for copper, about 1.64 times as much. Aluminum works by going up in size: on a 50 A, 240 V circuit with a 100 foot run, 4 AWG aluminum drops 5.08 V (2.12 percent), close to the 4.91 V (2.05 percent) of 6 AWG copper. Aluminum conductors also need terminals identified for aluminum.

How do you calculate three phase voltage drop?

A balanced three phase circuit uses the square root of 3, about 1.732, in place of the 2 used for single phase, because the phase currents return on the other phase conductors instead of a separate return wire. The formula is VD = 1.732 × L × R × I ÷ 1,000, with L the one way length in feet. Example: 100 A over 300 feet of 1/0 AWG aluminum at 0.201 ohms per 1,000 feet on a 480 V system gives 1.732 × 300 × 0.201 × 100 ÷ 1,000 = 10.44 V, or 2.18 percent of the line to line voltage.

How much voltage drop is acceptable on a 12 volt DC system?

The NEC informational notes give 3 and 5 percent for power, heating and lighting loads, and at 12 V those are only 0.36 V and 0.6 V, so low voltage runs need much larger wire for their current. A 10 A load on a 20 foot run of 10 AWG copper drops 2 × 20 × 1.24 × 10 ÷ 1,000 = 0.496 V, which is 4.13 percent. Keeping that load under 3 percent on 10 AWG limits the one way run to about 14.5 feet. Also check the minimum input voltage in the equipment instructions.

Sources & References

  • National Fire Protection Association. NFPA 70, National Electrical Code, document information page (current edition and free access to the code text). nfpa.org
  • NFPA 70, Chapter 9, Table 8 Conductor Properties (DC resistance at 75 °C, areas, temperature note), 2011 edition reproduction hosted by NECA IBEW Electricians; the 2017 values are identical. necaibewelectricians.com
  • IAEI Magazine. Voltage Drop Formulas, April 5, 2017 (K factors, formulas, informational note sections, 90.5(C), 647.4(D)). iaeimagazine.org
  • Lamendola, M. Tip of the Week: Insights from NEC Article 90, Part 4, EC&M, August 28, 2017 (voltage drop notes are explanatory, not requirements). ecmweb.com
  • National Bureau of Standards. Copper Wire Tables, Handbook 100, 1966 (International Annealed Copper Standard, 1.7241 μΩ·cm and 0.017241 Ω·mm²/m at 20 °C, coefficient 0.00393). nist.gov
  • National Bureau of Standards. Aluminum Wire Tables, Handbook 109, 1972 (61 percent IACS aluminum, 0.028264 Ω·mm²/m at 20 °C, coefficient 0.00403). nist.gov

Results are estimates from conductor resistance and do not replace a design by a qualified person or review by your local inspector. Every number on this page was recomputed with the same formulas the calculator uses. Methodology reviewed: 2026.